Posted on 12-06-2011
Filed Under (linux, programming, shell script) by admin

Most networks rely on services to run all the time, whether it is MySQL for database, or Apache for web services, the fact of the matter is that those services need to be available all the time; therefore, admins need to make sure those services are running. So here’s a simple, yet efficient script that checks whether a service is running, and if it’s not, it tries to restart the service 3 times, if it fails to start the service; then, it proceeds to notify the user by emailing the log file. You can change the “service” variable to suit your needs depending on the service. Also, you could add more services and use a “for” loop to iterate through every single service. This script kind of creates a starting point.

#!/bin/bash
#author: jorge L. Vazquez
#purpose: checking running services
 
email=root
service=apache2
count=0
threshold=2
servicelog=/var/log/$service.log
 
#checking if service is running
ps -e | grep $service > /dev/null
servicestat=$(echo $?)
 
#if service not running lets try restart 3 times
if [ "$servicestat" != 0 ]; then 
 
	while [ "$count" -le "$threshold" ]
	do
		#attempt to start the service
		/etc/init.d/$service start >> $servicelog 2>&1
		if [ $? != 0 ]; then
			((count=count+1))
		else
			exit 0  #if service started exit
		fi
	done
	#if service could not be started, notify
	cat $servicelog | mail -s "problem starting $service" $email 2>/dev/null
fi
 
#END

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Posted on 20-05-2011
Filed Under (linux, programming, shell script, ubuntu) by admin

Going through different log files can be a pain, but here’s a simple script that parses today’s logs from different files into a single file, in this case we extract today’s logs from messages, auth.log, syslog. Finally, we send them through email. Don’t forget to make the file executable!… Logparser can be downloaded from here

#!/bin/bash
#author jorge
#purpose: extracting daily log entries from multiple log files
 
LOG1=/var/log/messages
LOG2=/var/log/auth.log
LOG3=/var/log/syslog
MYDATE=`date +%b\ %d`
OUTPUTLOG=`date +%F`.dailylog
EMAIL=btuser
 
for LOG in $LOG{1,2,3}
do
        #if file exist and is not empty then process
        if [ -e $LOG ] && [ -s $LOG ]; then
                echo $LOG BEGIN >> $OUTPUTLOG
                #only grabbing todays log out of file
                grep -E "$MYDATE" $LOG >> $OUTPUTLOG 2>/dev/null
                echo $LOG END >> $OUTPUTLOG
                echo >> $OUTPUTLOG
        fi
done
 
#email output
cat $OUTPUTLOG | mail -s "daily logs `date +%F`" $EMAIL 2>/dev/null
 
#END

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Posted on 28-03-2011
Filed Under (C++, programming) by admin
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#include <iostream>
#include <string>
using namespace std;
 
class TicTacToe
{
private: 
	char table[3][3];
public:
	TicTacToe() { }
	//insert numbers
	void setTable()
	{
		int n = 1;
		for(int i = 0; i < 3; i++)
		{
			for(int j = 0; j < 3; j++)
			{
				table[i][j] = '0' + n;//cast n to char
				n++;
			}
		}
	}
	//output table to screen
	void printTable()
	{
		for(int i = 0; i < 3; i++)
		{
			for(int j = 0; j < 3; j++)
				if(j < 2) { cout << table[i][j] << "|"; }
				else { cout << table[i][j] << endl; }
			if(i < 2) { cout << "-+-+-\n"; }
		}
	}
	//player move and set to X or O
	void playerMove(char num, char player)
	{
		bool wrongMove = true;//wrong move
		for(int i = 0; i < 3; i++)
		{
			for(int j = 0; j < 3; j++)
			{//mark square with X or O
				if(table[i][j] == num) { table[i][j] = player; wrongMove = false; }
			}
		}
		if(wrongMove == true) { cout << "Wrong move!\n"; }
	}
	//cheking for winers
	bool checkWinner(char player, bool gameOver)
	{
		//winning conditions
		for(int i = 0; i < 3; i++)//checking rows
			if(table[i][0] == table[i][1] && table[i][1] == table[i][2]) gameOver = true;
		for(int i = 0; i < 3; i++)//checking columns
			if(table[0][i] == table[1][i] && table[1][i] == table[2][i]) gameOver = true;
		//diagonals
		if(table[0][0] == table[1][1] && table[1][1] == table[2][2]) gameOver = true;
		if(table[0][2] == table[1][1] && table[1][1] == table[2][0]) gameOver = true;
		if(gameOver == true) 
		{
			cout << "Player " << player << " wins!\n\n";
		}
		return gameOver;
	}
	//checking for a draw
	bool checkDraw(bool gameOver)
	{
		int n = 1, count = 0;
		for(int i = 0; i < 3; i++)
		{
			for(int j = 0; j < 3; j++)
			{
				//cheking if board is full
				if(table[i][j] == '0'+n) { count++; }
				n++;
			}
		}
		if(count < 1) { cout << "It's a draw!\n\n"; gameOver = true; }
		return gameOver;
	}
};
 
int main()
{
	bool done = false, gameOver = false;
	char player = 'O', num;
	TicTacToe myGame;
	myGame.setTable();
	do
	{
		if(player == 'X') { player = 'O'; }
		else { player = 'X'; } 
		myGame.printTable();
		cout << "Player \"" << player << "\" turn or (q) to quit> ";
		cin >> num; 
		cout << "\n";
		if(num == 'q') { cout << "Goodbye!...\n"; break; }
		myGame.playerMove(num, player);
		gameOver = myGame.checkWinner(player, gameOver);
		gameOver = myGame.checkDraw(gameOver);
		//if game over, starting over
		if(gameOver == true) 
		{	myGame.setTable(); 
			gameOver = false; 
		}
	}while(!done);
 
	system("pause");
	return 0;
}

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Posted on 12-03-2011
Filed Under (C++, programming) by admin

BracketingSearch from cplusplus. The solution to computer guessing the number the user is thinking is achieve best by using Binary Search. A binary search locates a value in a sorted array by determining whether the value occurs in the first or second half, then repeating the search in one of the halves. In this case the computer start with a range 1 – 100, and using the num = (1 + 100) / 2 formula the computer continually adjust the range until it guesses the number.

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//Guessing game: the computer guess the 
//number that the user is thinking. 
//this is done by using Binary Search algorithm
#include <iostream>
using namespace std;
 
int guessNumber(int& l, int& h, int& m, char c);
void guessRight(int&, int&, int&, int&);
 
 
int main()
{
    int low = 0, high = 100, count = 0, mid = 0;
	char a;
	do
	{
		if(count == 0) //star game over
		{
            system("cls");
			cout << "Think a number from 1 - 100. \n";
			system("pause");
			cout << "\n\n";
			mid = guessNumber(low, high, mid, a);
		}
		count++;//count and menu
		cout << "Is your number " << mid << " ?\n";
		cout << "Enter (c) for correct\n";
		cout << "Enter (l) if number is low\n";
		cout << "Enter (h) if number is high\n";
		cout << "Enter (q) to quit\n";
		cin >> a;
		if(a == 'c') { guessRight(count, high, low, mid); }
		else if(a == 'l') { mid = guessNumber(low, high, mid, a); }
		else if(a == 'h') { mid = guessNumber(low, high, mid, a); }
		else if(a == 'q') { cout << "Goodbye!\n"; break; }
		else { cout << "Wrong choice try again\n"; }
	}while(a != 'q');
 
	system("pause");
	return 0;
}
//binary search
int guessNumber(int& low, int& high, int& mid, char a)
{
	if(a == 'l') { low = mid + 1; }//if number is low
	if(a == 'h') { high = mid - 1; }//if number is high
	int m = (high + low) / 2;
	return m;
}
void guessRight(int& count, int& high, int& low, int& mid)//guess right
{
	cout << "Congrats, you guessed in " << count << " tries!\n\n";
	high = 100; low = 0; mid = 0; count = 0;//reseting all num
	system("pause");
 
}

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Posted on 12-03-2011
Filed Under (C++, programming) by admin

This is the solution to PancakeGlutton exercise from cplusplus.com. Printing out an array of number in descending or ascending order can be accomplish with out doing any type of sort. ok, let’s say you want to find out how may pancakes a every person ate, and then output in descending order starting with the most pancakes. In this case the output is in descending order, so all you have to do is find the biggest number and then decrease by one and print every number in the array. Here’s an example.

#include <iostream>
#include <string>
using namespace std;
int main()
{
	int persons[10]; 
	for(int i = 0; i < 10; i++)
	{
		cout << "Enter how many pancakes person " << i << " ate: ";
		cin >> persons[i];
	}
	//finding biggest and smallest
	int small = persons[0], big = persons[0], idSmall, idBig;
	for(int j = 0; j < 10; j++)
	{
		if(small > persons[j]) { small = persons[j]; idSmall = j; }
		if(big < persons[j]) { big = persons[j]; idBig = j; }
	}
 
	cout << "The person who ate the most pancakes > " << idBig << endl;
	cout << "The person who ate the least pancakes > " << idSmall << endl;
 
	//output in descending order starting with most pancakes
	for(big; big >= 0; big--)
	{
		for(int i = 0; i < 10; i++)
		{
		    if(persons[i] == big) { cout << "Person " << i << " ate " << big << endl; }
		}
	}
	system("pause");
	return 0;
}

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Posted on 20-02-2011
Filed Under (C++, programming) by admin

Finding whether a word or number is a palindrome is very common in programming languages. A palindrome word or number is one that reads the same in either direction. Words: bob, boob, ana… Numbers: 1, 2, 33, 121, 222, 3445443.

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#include <iostream>
#include <string>
using namespace std;
//finding palindromes
int main()
{
	cout << "Enter word or number: ";
	string temp, input; cin >> input;
	temp = input;
 
	reverse(input.begin(), input.end());//reversing input
	if(temp == input) { cout << temp << " is a palindrome!" << endl; } //checking for palin
	else { cout << temp << " is not a palindrome!" << endl; }
 
	system("pause");
	return 0;
}

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Posted on 20-02-2011
Filed Under (C++, programming) by admin

Finding the minimum and maximum in an array is a classical programming exercise in C++. Here’s how is done!

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#include <iostream>
using namespace std;
//finding min and max in array
int main()
{
	int num[5] = { 2, 50, 100, 25, 78 };
	int max = num[0], min = num[0]; //set max & min to some value
	for(int i = 0; i < 5; i++)//loop through array
	{
		if(num[i] > max) { max = num[i]; } //find max
		if(num[i] < min) { min = num[i]; } //find min
	}
	cout << "Maximum number: " << max << endl;
	cout << "Minimum number: " << min << endl;
 
	system("pause");
	return 0;
}

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